1 does NOT equal .999999......
but...
if 1/3 = .333.....
and 2/3 = .666.....
and 1/3 + 2/3 = 3/3 or 1
but .333... + .666.... = .999..... not 1.
1/3 + 2/3 = 3/3 or 1
.. =..................=.....................=/=
.333.... + .666... = .999.....
WHAAAAAAAAAAAAAAAT?
long story short this guy in my class wont get off about him being "right" about 1 = .999.....
which i know it doesnt...
how do i prove him wrong?
the thing is your adding an infinite amount of numbers.
.333(infinate) + .666(infinate) = 1, not .999
Well, if it's infinite that means that the 9s or 6s go on forever to the point where you can never round up to a whole 1.0
But of course because it's infinite the number is so close to 1.0 that it's true value is insignificant and can is just written as 1.
That's the best I can do.
Long story short, just twist what he said around.
If 1/3 = 0.333...etc and 2/3 = 0.666...etc and 3/3 =1
Therefore, 0.333...etc + 0.666...etc must equal 1.0000
And also tell him he's a moron for thinking 0.9999999 is equal to 1
yeah, 1/3+2/3=1 no matter how you put it
It's a curve. .333 does NOT equal 1/3. The 3 will go on forever and ever. His math isn't wrong, just his assumption. Just because we don't have a great simple way to define 1/3 in decimal does not mean that he can take the simplified version of 1/3 converted into decimal and create a new equation.
The mistake is when assuming that a number to infinity adds just like a base number. Example:
3 + 3 = 6
3 + 3 + 3 = 9
3 infinity + 3 infinity = 6 infinity
3 infinity + 3 infinity + 3 infinity = 10
Tell him to get a life and leave you alone.
NERDS.
Lol I half sleep in Math, then listen to some Nas.
.99999... (w/ the 9 repeating infinitely) is equivalent to one. however if he truncated the decimal values for 1/3 or 2/3 than his argument is wrong. but to truly prove it, he could define a sequence as a={.9,.99,.999,.9999, and so on infinitely} and show that the limit of 1 - a(n) approaches 0 as n approaches infinity.
0.999... is indeed equal to 1. Or to be more precise, there is an infinitely small gap between them, which is essentially the same as being equal.
Seriously...we need recurring symbols.
---.-----.---
0.3 0.6 (ignore -)
Yes it has already been answered above they are correct.
Haha, this is one of fundamental teaching of double precision floating-point numbers in C++:
To a computer -
1/3 = 0.3333333333333
Tell him to get a life and leave you alone.
bingo
Haha, this is one of fundamental teaching of double precision floating-point numbers in C++:
To a computer -
1/3 = 0.3333333333333
This was a C++ thread since when.
its...not?
but like its been said, 1/3 = .33333333...(inf) if you wanted to end the infinite repetition of numbers for easy written notation, you could chop it off at .3333 (or however many significant numbers you'd need/want. don't round up cause its too small to...
2/3 = .66666666, and to truncate it you'd round up to .6667.
therefore 3/3 = 1, because .3333 + .6667 = 1.
its...not?
...I know that.
*considers sarcasm tags for previous post*
He was just using an example Cappin'.
NERDS.
Lol I half sleep in Math, then listen to some Nas.
Matheletes FTW!
But yeah what everyone else has said.
1/3 = 0.333333333333........33333335
2/3 = 0.666666666666..etc...66666665
+ -------------------------------------
= 1 = 1
-------------------------------------
1/3 TENDS TO point 3
2/6 TENDS TO point 6
but they have to round at some point.
you can use round to closest, 3=3 6=7
or a negative round 3=4 6=6
either way 0.3recuring + 0.6recuring = 1
don't forget to round your infinate decimels. or you'll start to lose your mind